EasyMock: How do I create a mock of a genericized class without a warning?


The code

private SomeClass<Integer> someClass;
someClass = EasyMock.createMock(SomeClass.class);

gives me a warning "Type safety: The expression of type SomeClass needs unchecked conversion to conform to SomeClass<Integer>".


I know this goes against the question, but why not create a List rather than a Mock List?

It's less code and easier to work with, for instance if you want to add items to the list.

MyItem myItem = createMock(myItem.class);
List<MyItem> myItemList = new ArrayList<MyItem>();

Instead of

MyItem myItem = createMock(myItem.class);
List<MyItem> myItemList = createMock(ArrayList.class);
By : chim

I worked around this problem by introducing a subclass, e.g.

private abstract class MySpecialString implements MySpecial<String>{};

Then create a mock of that abstract class:

MySpecial<String> myMock = createControl().createMock(MySpecialString.class);

AFAIK, you can't avoid the unchecked warning when a class name literal is involved, and the SuppressWarnings annotation is the only way to handle this.

Note that it is good form to narrow the scope of the SuppressWarnings annotation as much as possible. You can apply this annotation to a single local variable assignment:

public void testSomething() {

    Foo<Integer> foo = EasyMock.createMock(Foo.class);

    // Rest of test method may still expose other warnings

or use a helper method:

private static <T> Foo<T> createFooMock() {
    return (Foo<T>)EasyMock.createMock(Foo.class);

public void testSomething() {
    Foo<String> foo = createFooMock();

    // Rest of test method may still expose other warnings
By : Barend

This video can help you solving your question :)
By: admin