Why is my ternary expression not working?


I am trying to set a flag to show or hide a page element, but it always displays even when the expression is false.

$canMerge = ($condition1 && $condition2) ? 'true' : 'false';
<?php if ($canMerge) { ?>Stuff<?php } ?>

What's up?

By : Polsonby

$canMerge = ($condition1 && $condition2);


if ($canMerge){
    echo "Stuff";
By : AnowarCst

Seems to me a reasonable question especially because of the discrepancy in the way PHP works.

For instance, the following code will output 'its false'

$a = '0';

    echo 'its true';
    echo 'its false';
By : depz123

This is broken because 'false' as a string will evaluate to true as a boolean.

However, this is an unneeded ternary expression, because the resulting values are simple true and false. This would be equivalent:

$canMerge = ($condition1 && $condition2);

This video can help you solving your question :)
By: admin