Java file extension regex

Tags: regex java
By : Dónal

I'm trying to come up with a Java regex that will match a filename only if it has a valid extension. For example it should match "" and "foo.b", but neither "foo." nor "foo".

I've written the following test program

public static void main(String[] args) {
  Pattern fileExtensionPattern = Pattern.compile("\\.\\w+\\z");

  boolean one = fileExtensionPattern.matcher("").matches();
  boolean two = fileExtensionPattern.matcher("foo.b").matches();
  boolean three = fileExtensionPattern.matcher("foo.").matches();
  boolean four = fileExtensionPattern.matcher("foo").matches();

  System.out.println(one + " " + two + " " + three + " " + four);

I expect this to print "true true false false", but instead it prints false for all 4 cases. Where am I going wrong?

Cheers, Don

By : Dónal

package regularexpression;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class RegularFile {
    public static void main(String[] args) {
        new RegularFile();

    public RegularFile() {

        String fileName = null;
        boolean bName = false;
        int iCount = 0;
        File dir = new File("C:/regularfolder");
        File[] files = dir.listFiles();
        System.out.println("List Of Files ::");

        for (File f : files) {

            fileName = f.getName();

            Pattern uName = Pattern.compile(".**");
            Matcher mUname = uName.matcher(fileName);
            bName = mUname.matches();
            if (bName) {

        System.out.println("File Count In Folder ::" + iCount);

By : hanisa

public boolean isFilename(String filename) {
    int i=filename.lastInstanceOf(".");
    return(i != -1 && i != filename.length - 1)

Would be significantly faster and regardless of what you do, putting it in a method would be more readable.

By : Bill K

The Matcher.matches() function tries to match the pattern against the entire input. Thus, you have to add .* to the beginning of your regex (and the \\Z at the end is superfluous, too), or use the find() method.

This video can help you solving your question :)
By: admin