I have two questions here :
1)> What is happening in line 2.The 'la' pseudo instruction refers to load address, instead of the literal '3444' there should have been a label.How can it load the address of the literal
2)> if you replace line 3 with "li $a0 3444" which loads 3444 into the register #a0 instead of the address.The output is still the same.What i want to ask from this is that how could syscall know that in #a0 is the address of the variable or the variable itself.How could the subroutine for printing the integer work correctly whether the argument stored in #a0 is the address or the integer value itself.
.text li $v0 1 >>2 la $a0 3444 # When i replace 3444 literal with the label 'anint' it makes sense and the output of course is the same syscall .data anint: .word 3444
UPDATE#2: I could'nt post the code in a comment so...
IF la(load address) and li(load immediate) both translate to the same instruction i-e loading the literal into #a0 then explain Line 3 from the code segment below.
.text li #v0 4 >>3 la #a0 msg #This loads the address of the label 'msg in #a0' not the label itself syscall .data msg: .asciiz "This is a long string that can't be saved in the register!"